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-4m^2+17m-15=0
a = -4; b = 17; c = -15;
Δ = b2-4ac
Δ = 172-4·(-4)·(-15)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*-4}=\frac{-24}{-8} =+3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*-4}=\frac{-10}{-8} =1+1/4 $
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